You just go on hitting blocks and more blocks to no end, and it gets annoying after a while. Speaking of which, DX-Ball's biggest problem is complete lack of dynamic (err, is that even a noun?) The game becomes frustrating for the simple reason that NOTHING HAPPENS. This might have been acceptible in the days of Arkanoid, but the lack of background really hampers the game's visual appeal. While the game is smooth and the graphics are decent, they are still extremely bland, as the game has absolutely no background. My dad's still struggling to get there :-) It's also quite challenging at the higher levels though I haven't really bothered playing it too much, I still found reaching my 59,000 points highscore quite challenging to attain, which is definitely good. With decent level design at worst and non-stop gaming, DX-Ball manages to remain quite addictive to the point that my dad still plays it night by night. It does so quite well really DX-Ball features pretty good graphics and manages to run just fine with an MP3 in the background on my old P166. It is relatively new, but tries very hard to stay oldskool and "Amiga"-esque with smooth animations and continuous, smooth gameplay. But I'm digressing.ĭX-Ball is undoubtedly one of the better breakout clones ever made for the PC. Luckily it can emulate most of these computers to an extent great enough that you can experience those great games again. It doesn't even come close to the wealth of arcade games available on the Commodore 64 or my personal favorite, the Amiga. There are very few genuinely good breakout clones on the PC, most notably Arkanoid (and its sequel) and Krypton Egg. To be honest, the PC is horribly lacking in good arcade games. I dont have my calculator on me so Ill leave you to solve for dX.A decent Breakout clone, but nothing to write home about. Also, since dX is the change in height in the spring, the change in height for the ball must be dX +. On the right hand side, we take into account that the energy will be conserved and distributed both to the potential energy of the spring as well *** the ball. The portion on the left of the equals sign is all the energy at point one. we can relate the kinetic energy the ball has at point one to the potential energy it will have at point two in this equation: (1/2)m(Vo^2) = (1/2)k(dX^2) + mg(dX+.4) hopefully this equation makes sense to you. For ease of calculation we will also set point one as zero height. to start this off we will break this problem down into two points: point 1 where the ball is just being thrown up and the point where the ball has maximally compressed the spring.
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